将文件转换为多部分文件

java groovy spring

2022-08-31 13:36:29

有没有办法将File对象转换为MultiPartFile？这样我就可以把这个对象发送到接受接口对象的方法？MultiPartFile

File myFile = new File("/path/to/the/file.txt")

MultiPartFile ....?

def (MultiPartFile file) {
  def is = new BufferedInputStream(file.getInputStream())
  //do something interesting with the stream
}

答案 1

MockMultipartFile就是为此目的而存在的。就像在您的代码段中一样，如果文件路径已知，下面的代码适用于我。

import java.nio.file.Files;
import java.nio.file.Path;
import java.nio.file.Paths;
import org.springframework.mock.web.MockMultipartFile;

Path path = Paths.get("/path/to/the/file.txt");
String name = "file.txt";
String originalFileName = "file.txt";
String contentType = "text/plain";
byte[] content = null;
try {
    content = Files.readAllBytes(path);
} catch (final IOException e) {
}
MultipartFile result = new MockMultipartFile(name,
                     originalFileName, contentType, content);

答案 2

File file = new File("src/test/resources/input.txt");
FileInputStream input = new FileInputStream(file);
MultipartFile multipartFile = new MockMultipartFile("file",
            file.getName(), "text/plain", IOUtils.toByteArray(input));