java 持久性本机 sql 不接受参数

java persistence sql oracle

2022-09-03 06:08:35

我的查询是

sql = "SELECT SUM(TOTAL_BYTES_DELIVERED) / SUM(TOTAL_TIME_TAKEN_IN_DELIVERY) 
         FROM MV_MFT_TRANSFER 
        WHERE TRANSFER_INITIATION_TIME > :startDate 
          AND TRANSFER_INITIATION_TIME < :endDate"

Query query = em.createNativeQuery(sql);
query.setParameter("startDate", startDate, TemporalType.DATE);
query.setParameter("endDate", endDate, TemporalType.DATE);
query.getResultList();'

当我运行此程序时，我收到一个错误

SQLExceptionTHrown: 
<Sep 11, 2012 12:50:46 PM PDT> <Warning> <EclipseLink> <BEA-2005000> <2012-09-11 12:50:46.893--UnitOfWork(1387841584)--Exception [EclipseLink-4002] (Eclipse Persistence Services - 2.4.1.v20120804-d768c4f): org.eclipse.persistence.exceptions.DatabaseException
Internal Exception: java.sql.SQLException: Missing IN or OUT parameter at index:: 1
Error Code: 17041
Call: SELECT SUM(TOTAL_BYTES_DELIVERED) / SUM(TOTAL_TIME_TAKEN_IN_DELIVERY) FROM MV_MFT_TRANSFER WHERE TRANSFER_INITIATION_TIME > :startDate AND TRANSFER_INITIATION_TIME < :endDate
Query: DataReadQuery(sql="SELECT SUM(TOTAL_BYTES_DELIVERED) / SUM(TOTAL_TIME_TAKEN_IN_DELIVERY) FROM MV_MFT_TRANSFER WHERE TRANSFER_INITIATION_TIME > :startDate AND TRANSFER_INITIATION_TIME < :endDate")> 
***SQLException in init() TRANSFER METRICS BEAN****
Local Exception Stack: 
Exception [EclipseLink-4002] (Eclipse Persistence Services - 2.4.1.v20120804-d768c4f): org.eclipse.persistence.exceptions.DatabaseException
Internal Exception: java.sql.SQLException: Missing IN or OUT parameter at index:: 1

答案 1

以下解决方案应该有效：

sql = "SELECT SUM(TOTAL_BYTES_DELIVERED) / SUM(TOTAL_TIME_TAKEN_IN_DELIVERY) 
         FROM MV_MFT_TRANSFER 
        WHERE TRANSFER_INITIATION_TIME > ?
          AND TRANSFER_INITIATION_TIME < ?"

Query query = em.createNativeQuery(sql);
query.setParameter(1, startDate, TemporalType.DATE);
query.setParameter(2, endDate, TemporalType.DATE);
query.getResultList();

似乎如果您使用位置参数，它将起作用。不能合并命名参数和本机查询。以下是一些链接：

http://java.boot.by/scbcd5-guide/ch08s05.html

http://www.wisegeek.com/what-are-native-queries.htm

还有更多，只需谷歌搜索：“只有位置参数绑定可以移植用于本机查询”。

编辑：更多链接到具有类似问题的问题：

如何从 JDBC 查询中获取所有元素

JPA/休眠本机查询无法识别参数

答案 2

这篇文章真的很有帮助！

http://software-security.sans.org/developer-how-to/fix-sql-injection-in-java-persistence-api-jpa

文章的要点是：

这些是不安全的查询，不要使用它！字符串串联不好：

List results = entityManager.createQuery("Select order from Orders order where order.id = " + orderId).getResultList();
List results = entityManager.createNativeQuery("Select * from Books where author = " + author).getResultList();
int resultCode = entityManager.createNativeQuery("Delete from Cart where itemId = " + itemId).executeUpdate();

这些是安全的查询。

/* positional parameter in JPQL */
Query jpqlQuery = entityManager.createQuery("Select order from Orders order where order.id = ?1");
List results = jpqlQuery.setParameter(1, "123-ADB-567-QTWYTFDL").getResultList();

/* named parameter in JPQL */
Query jpqlQuery = entityManager.createQuery("Select emp from Employees emp where emp.incentive > :incentive");
List results = jpqlQuery.setParameter("incentive", new Long(10000)).getResultList();

/* named query in JPQL - Query named "myCart" being "Select c from Cart c where c.itemId = :itemId" */
Query jpqlQuery = entityManager.createNamedQuery("myCart");
List results = jpqlQuery.setParameter("itemId", "item-id-0001").getResultList();

/* Native SQL */
Query sqlQuery = entityManager.createNativeQuery("Select * from Books where author = ?", Book.class);
List results = sqlQuery.setParameter(1, "Charles Dickens").getResultList();