弹簧规格和可分页

java hibernate spring specifications spring-data

2022-09-03 07:13:12

我该如何使用和一起使用？SpecificationPageable

人员存储库.java

@Query("SELECT e FROM PersonelEntity e ")
List<PersonelEntity> findData(Specification<PersonelEntity>  test, Pageable pageable);

人员服务.java

public List<PersonelEntity> filteredData(Specification<PersonelEntity> filter,Pageable  pageable){
    List<PersonelEntity> filteredData = personelRepository.findData(filter,pageable);
    return filteredData;
}

人员控制者.java

Pageable reqCount = new PageRequest(0, 10);
Specification<PersonelEntity> filter = new FilterSpecification<PersonelEntity>(new SearchCriteria("name", "=","lux"));
personels = personelService.findData(filter,reqCount);

当我运行它时，我得到这样的错误。但是如果我像 findAll（可分页页面）和 findAll（规范过滤器）一样单独调用 findAll（）函数，它就可以工作了。但我不能一起使用它。

java.lang.IllegalArgumentException: Parameter with that position [1] did not exist
    at org.hibernate.jpa.spi.BaseQueryImpl.findParameterRegistration(BaseQueryImpl.java:502) ~[hibernate-entitymanager-5.0.12.Final.jar:5.0.12.Final]
    at org.hibernate.jpa.spi.BaseQueryImpl.setParameter(BaseQueryImpl.java:692) ~[hibernate-entitymanager-5.0.12.Final.jar:5.0.12.Final]
    at org.hibernate.jpa.spi.AbstractQueryImpl.setParameter(AbstractQueryImpl.java:181) ~[hibernate-entitymanager-5.0.12.Final.jar:5.0.12.Final]
    at org.hibernate.jpa.spi.AbstractQueryImpl.setParameter(AbstractQueryImpl.java:32) ~[hibernate-entitymanager-5.0.12.Final.jar:5.0.12.Final]
    at org.springframework.data.jpa.repository.query.ParameterBinder.bind(ParameterBinder.java:141) ~[spring-data-jpa-1.11.1.RELEASE.jar:na]
    at org.springframework.data.jpa.repository.query.StringQueryParameterBinder.bind(StringQueryParameterBinder.java:61) ~[spring-data-jpa-1.11.1.RELEASE.jar:na]
    at org.springframework.data.jpa.repository.query.ParameterBinder.bind(ParameterBinder.java:101) ~[spring-data-jpa-1.11.1.RELEASE.jar:na]
    at org.springframework.data.jpa.repository.query.SpelExpressionStringQueryParameterBinder.bind(SpelExpressionStringQueryParameterBinder.java:69) ~[spring-data-jpa-1.11.1.RELEASE.jar:na]
    at org.springframework.data.jpa.repository.query.ParameterBinder.bindAndPrepare(ParameterBinder.java:161) ~[spring-data-jpa-1.11.1.RELEASE.jar:na]
    at org.springframework.data.jpa.repository.query.ParameterBinder.bindAndPrepare(ParameterBinder.java:152) ~[spring-data-jpa-1.11.1.RELEASE.jar:na]
    at org.springframework.data.jpa.repository.query.AbstractStringBasedJpaQuery.doCreateQuery(AbstractStringBasedJpaQuery.java:81) ~[spring-data-jpa-1.11.1.RELEASE.jar:na]
    at org.springframework.data.jpa.repository.query.AbstractJpaQuery.createQuery(AbstractJpaQuery.java:190) ~[spring-data-jpa-1.11.1.RELEASE.jar:na]
    at org.springframework.data.jpa.repository.query.JpaQueryExecution$CollectionExecution.doExecute(JpaQueryExecution.java:121) ~[spring-data-jpa-1.11.1.RELEASE.jar:na]
    at org.springframework.data.jpa.repository.query.JpaQueryExecution.execute(JpaQueryExecution.java:85) ~[spring-data-jpa-1.11.1.RELEASE.jar:na]

答案 1

通过编辑 personelService.java和删除 personelRepository 上的 findData 函数来解决。我使用springframework.data.jpa.repository.JpaRepository findAll（）函数，它可以工作。

public List<PersonelEntity> filteredData (Specification<PersonelEntity> spec, Pageable pageable){
    Page<PersonelEntity> pageData = personelRepository.findAll(spec,pageable);
    List<PersonelEntity> filteredData = pageData.getContent();
    return filteredData;
}

答案 2