如何计算两个Java java.sql.Timestamps之间的差异？

timestamp java

2022-09-03 06:20:18

请包括纳米，否则这将是微不足道的：

long diff = Math.abs(t1.getTime () - t2.getTime ());

[编辑]我想要最精确的结果，所以没有双打;仅整数/长整型算术。此外，结果必须是正数。伪代码：

Timestamp result = abs (t1 - t2);

例子：

t1 = (time=1001, nanos=1000000), t2 = (time=999, nanos=999000000)
 -> diff = (time=2, nanos=2000000)

是的，java中的毫秒.sql.Timestamp在时间和nans par中是重复的，所以1001毫秒意味着1秒（1000）和1毫，这是在部分和部分，因为1毫秒= 1000000纳秒）。这比看起来要狡猾得多。timenanos

我建议在没有实际测试代码或准备好工作代码示例的情况下不要发布答案:)

答案 1

经过一个小时和各种单元测试，我想出了这个解决方案：

public static Timestamp diff (java.util.Date t1, java.util.Date t2)
{
    // Make sure the result is always > 0
    if (t1.compareTo (t2) < 0)
    {
        java.util.Date tmp = t1;
        t1 = t2;
        t2 = tmp;
    }

    // Timestamps mix milli and nanoseconds in the API, so we have to separate the two
    long diffSeconds = (t1.getTime () / 1000) - (t2.getTime () / 1000);
    // For normals dates, we have millisecond precision
    int nano1 = ((int) t1.getTime () % 1000) * 1000000;
    // If the parameter is a Timestamp, we have additional precision in nanoseconds
    if (t1 instanceof Timestamp)
        nano1 = ((Timestamp)t1).getNanos ();
    int nano2 = ((int) t2.getTime () % 1000) * 1000000;
    if (t2 instanceof Timestamp)
        nano2 = ((Timestamp)t2).getNanos ();

    int diffNanos = nano1 - nano2;
    if (diffNanos < 0)
    {
        // Borrow one second
        diffSeconds --;
        diffNanos += 1000000000;
    }

    // mix nanos and millis again
    Timestamp result = new Timestamp ((diffSeconds * 1000) + (diffNanos / 1000000));
    // setNanos() with a value of in the millisecond range doesn't affect the value of the time field
    // while milliseconds in the time field will modify nanos! Damn, this API is a *mess*
    result.setNanos (diffNanos);
    return result;
}

单元测试：

    Timestamp t1 = new Timestamp (0);
    Timestamp t3 = new Timestamp (999);
    Timestamp t4 = new Timestamp (5001);
    // Careful here; internally, Java has set nanos already!
    t4.setNanos (t4.getNanos () + 1);

    // Show what a mess this API is...
    // Yes, the milliseconds show up in *both* fields! Isn't that fun?
    assertEquals (999, t3.getTime ());
    assertEquals (999000000, t3.getNanos ());
    // This looks weird but t4 contains 5 seconds, 1 milli, 1 nano.
    // The lone milli is in both results ...
    assertEquals (5001, t4.getTime ());
    assertEquals (1000001, t4.getNanos ());

    diff = DBUtil.diff (t1, t4);
    assertEquals (5001, diff.getTime ());
    assertEquals (1000001, diff.getNanos ());

    diff = DBUtil.diff (t4, t3);
    assertEquals (4002, diff.getTime ());
    assertEquals (2000001, diff.getNanos ());

答案 2

我使用此方法获取2之间的差异java.sql.Timestmap

/**
 * Get a diff between two timestamps.
 *
 * @param oldTs The older timestamp
 * @param newTs The newer timestamp
 * @param timeUnit The unit in which you want the diff
 * @return The diff value, in the provided time unit.
 */
public static long getDateDiff(Timestamp oldTs, Timestamp newTs, TimeUnit timeUnit) {
    long diffInMS = newTs.getTime() - oldTs.getTime();
    return timeUnit.convert(diffInMS, TimeUnit.MILLISECONDS);
}

// Examples:
// long diffMinutes = getDateDiff(oldTs, newTs, TimeUnit.MINUTES);
// long diffHours = getDateDiff(oldTs, newTs, TimeUnit.HOURS);