Spring Data JPA规范使用具有一对多关系的标准构建器
我有一个实体,一个实体和一个实体。UserUserToApplicationApplication
单个可以访问多个 .一个可以被多个使用。UserApplicationApplicationUser
下面是实体。User
@Entity
@Table(name = "USER", schema = "UDB")
public class User {
    private Long userId;
    private Collection<Application> applications;
    private String firstNm;
    private String lastNm;
    private String email;
    @SequenceGenerator(name = "generator", sequenceName = "UDB.USER_SEQ", initialValue = 1, allocationSize = 1)
    @Id
    @GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "generator")
    @Column(name = "USER_ID", unique = true, nullable = false)
    public Long getUserId() {
        return userId;
    }
    public void setUserId(Long userId) {
        this.userId = userId;
    }
    @OneToMany(mappedBy = "user", fetch = FetchType.LAZY)
    public Collection<Application> getApplications() {
        return applications;
    }
    public void setApplications(Collection<Application> applications) {
        this.applications = applications;
    }
    /* Other getters and setters omitted for brevity */
}
下面是实体。UserToApplication
@Entity
@Table(name = "USER_TO_APPLICATION", schema = "UDB")
public class Application {
    private Long userToApplicationId;
    private User user;
    private Application application;
    @SequenceGenerator(name = "generator", sequenceName = "UDB.USER_TO_APP_SEQ", initialValue = 0, allocationSize = 1)
    @Id
    @GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "generator")
    @Column(name = "USER_TO_APPLICATION_ID", unique = true, nullable = false)
    public Long getUserToApplicationId() {
        return userToApplicationId;
    }
    public void setUserToApplicationId(Long userToApplicationId) {
        this.userToApplicationId = userToApplicationId;
    }
    @ManyToOne
    @JoinColumn(name = "USER_ID", referencedColumnName = "USER_ID", nullable = false)
    public User getUser() {
        return user;
    }
    public void setUser(User user) {
        this.user = user;
    }
    @ManyToOne
    @JoinColumn(name = "APPLICATION_ID", nullable = false)
    public Application getApplication() {
        return application;
    }
}
这是实体。Application
@Entity
@Table(name = "APPLICATION", schema = "UDB")
public class Application {
    private Long applicationId;
    private String name;
    private String code;
    /* Getters and setters omitted for brevity */
}
我有以下用于搜索 by、 和 .SpecificationUserfirstNmlastNmemail
public class UserSpecification {
    public static Specification<User> findByFirstNmLastNmEmail(String firstNm, String lastNm, String email) {
        return new Specification<User>() {
            @Override
            public Predicate toPredicate(Root<User> root, CriteriaQuery<?> query, CriteriaBuilder cb) {
                final Predicate firstNmPredicate = null;
                final Predicate lastNmPredicate = null;
                final Predicate emailPredicate = null;
                if (!StringUtils.isEmpty(firstNm)) {
                    firstNmPredicate = cb.like(cb.lower(root.get(User_.firstNm), firstNm));
                }
                if (!StringUtils.isEmpty(lastNm)) {
                    lastNmPredicate = cb.like(cb.lower(root.get(User_.lastNm), lastNm));
                }
                if (!StringUtils.isEmpty(email)) {
                    emailPredicate = cb.like(cb.lower(root.get(User_.email), email));
                }
                return cb.and(firstNmPredicate, lastNmPredicate, emailPredicate);
            }
        };
    }
}
这是我到目前为止拥有的元模型。User_
@StaticMetamodel(User.class)
public class User_ {
    public static volatile SingularAttribute<User, String> firstNm;
    public static volatile SingularAttribute<User, String> lastNm;
    public static volatile SingularAttribute<User, String> email;
}
现在,我还想将应用程序 ID 列表传递给 ,以便其方法签名为:Specification
public static Specification<User> findByFirstNmLastNmEmailApp(String firstNm, String lastNm, String email, Collection<Long> appIds)
所以,我的问题是,如果我将映射添加到实体字段的元模型,那么我如何在?@OneToManyUser_Collection<Application> applicationsUserSpecification
我的当前查询类似于以下 SQL 查询:Specification
select * from user u
where lower(first_nm) like '%firstNm%'
and lower(last_nm) like '%lastNm%'
and lower(email) like '%email%';
我想在新作品中实现的将是这样的:Specification
select * from user u
join user_to_application uta on uta.user_id = u.user_id
where lower(u.first_nm) like '%firstNm%'
and lower(u.last_nm) like '%lastNm%'
and lower(u.email) like '%email%'
and uta.application_id in (appIds);
是否可以在元模型中进行这种映射,以及如何在我的?Specification