如何在Java中将条目添加到现有的zip文件中?

2022-09-03 13:37:45

可能的重复:
使用 Java 将文件追加到 zip 文件

使用 ZipOutputStream 打开该文件将覆盖它。有没有办法保留文件并只添加新条目?


答案 1

该函数将现有 zip 文件重命名为临时文件,然后将现有 zip 中的所有条目与新文件一起添加,但不包括与其中一个新文件同名的 zip 条目。

public static void addFilesToExistingZip(File zipFile,
         File[] files) throws IOException {
        // get a temp file
    File tempFile = File.createTempFile(zipFile.getName(), null);
        // delete it, otherwise you cannot rename your existing zip to it.
    tempFile.delete();

    boolean renameOk=zipFile.renameTo(tempFile);
    if (!renameOk)
    {
        throw new RuntimeException("could not rename the file "+zipFile.getAbsolutePath()+" to "+tempFile.getAbsolutePath());
    }
    byte[] buf = new byte[1024];

    ZipInputStream zin = new ZipInputStream(new FileInputStream(tempFile));
    ZipOutputStream out = new ZipOutputStream(new FileOutputStream(zipFile));

    ZipEntry entry = zin.getNextEntry();
    while (entry != null) {
        String name = entry.getName();
        boolean notInFiles = true;
        for (File f : files) {
            if (f.getName().equals(name)) {
                notInFiles = false;
                break;
            }
        }
        if (notInFiles) {
            // Add ZIP entry to output stream.
            out.putNextEntry(new ZipEntry(name));
            // Transfer bytes from the ZIP file to the output file
            int len;
            while ((len = zin.read(buf)) > 0) {
                out.write(buf, 0, len);
            }
        }
        entry = zin.getNextEntry();
    }
    // Close the streams        
    zin.close();
    // Compress the files
    for (int i = 0; i < files.length; i++) {
        InputStream in = new FileInputStream(files[i]);
        // Add ZIP entry to output stream.
        out.putNextEntry(new ZipEntry(files[i].getName()));
        // Transfer bytes from the file to the ZIP file
        int len;
        while ((len = in.read(buf)) > 0) {
            out.write(buf, 0, len);
        }
        // Complete the entry
        out.closeEntry();
        in.close();
    }
    // Complete the ZIP file
    out.close();
    tempFile.delete();
}

答案 2

您可以使用 来获取现有文件中所有对象的枚举,遍历它们并将它们全部添加到 中,然后另外添加新条目。zipFile.entries()ZipEntryZipOutputStream


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