Avro Java API Timestamp Logic Type？

time java avro

2022-09-04 06:37:57

使用Avro Java API，我可以制作一个简单的记录模式，例如：

    Schema schemaWithTimestamp = SchemaBuilder
            .record("MyRecord").namespace("org.demo")
            .fields()
            .name("timestamp").type().longType().noDefault()
            .endRecord();

如何使用逻辑类型标记架构字段，特别是：https://avro.apache.org/docs/1.8.1/api/java/org/apache/avro/LogicalTypes.TimestampMillis.html

答案 1

感谢DontPanic：

    Schema timestampMilliType = LogicalTypes.timestampMillis().addToSchema(Schema.create(Schema.Type.LONG));

    Schema schemaWithTimestamp = SchemaBuilder
            .record("MyRecord").namespace("org.demo")
            .fields()
            .name("timestamp_with_logical_type").type(timestampMilliType).noDefault()
            .name("timestamp_no_logical_type").type().longType().noDefault()
            .endRecord();

    System.out.println(schemaWithTimestamp.toString(true));

这导致：

{
  "type" : "record",
  "name" : "MyRecord",
  "namespace" : "org.demo",
  "fields" : [ {
    "name" : "timestamp_with_logical_type",
    "type" : {
      "type" : "long",
      "logicalType" : "timestamp-millis"
    }
  }, {
    "name" : "timestamp_no_logical_type",
    "type" : "long"
  } ]
}

答案 2

感谢第一个解决方案，现在是可为空的逻辑类型，如：

{ 
"name":"maturityDate",
  "type":["null", {
    "type":"long","logicalType":"timestamp-millis"
    }]
},

我想如下：

        Schema timestampMilliType = LogicalTypes.timestampMillis().addToSchema(Schema.create(Schema.Type.LONG));

        Schema clientIdentifier = SchemaBuilder.record("ClientIdentifier")
                .namespace("com.baeldung.avro")
                .fields()
                .requiredString("hostName")
                .requiredString("ipAddress")
                .name("maturityDate")
                .type()
                .unionOf()
                .nullType()
                .and()
                .type(timestampMilliType)
                .endUnion()
                .noDefault()
                .endRecord();