Java和全屏在多个显示器上

java fullscreen swing

2022-09-04 06:20:17

来自我的 Java 应用程序的片段：

 JFrame f = new JFrame();
 GraphicsEnvironment ge = GraphicsEnvironment.getLocalGraphicsEnvironment();
 GraphicsDevice gd = ge.getDefaultScreenDevice();
 gd.setFullScreenWindow(f);

所以它所做的是让它自己全屏。现在奇怪的是，该程序是全屏的，但只在一台显示器上！例如，我有一个Windows Vista系统，其中两个屏幕组合在一个桌面中。该怎么做才能自动让它在所有显示器上全屏显示？

好的，我试过了：

import java.awt.image.ColorModel;
import java.awt.GraphicsConfiguration;
import java.awt.GraphicsDevice;
import java.awt.GraphicsEnvironment;
import java.awt.Rectangle;

class grdevs
{
    public static void main(String [] args)
    {
        GraphicsEnvironment ge = GraphicsEnvironment.getLocalGraphicsEnvironment();
        GraphicsDevice[] gs = ge.getScreenDevices();
        for(GraphicsDevice curGs : gs)
        {
            GraphicsConfiguration[] gc = curGs.getConfigurations();
            for(GraphicsConfiguration curGc : gc)
            {
                Rectangle bounds = curGc.getBounds();
                ColorModel cm = curGc.getColorModel();

                System.out.println("" + bounds.getX() + "," + bounds.getY() + " " + bounds.getWidth() + "x" + bounds.getHeight() + " " + cm);
            }
        } 
    }
}

但它给出了：

0.0,0.0 1024.0x768.0 DirectColorModel: rmask=ff0000 gmask=ff00 bmask=ff amask=0
0.0,0.0 1024.0x768.0 DirectColorModel: rmask=ff0000 gmask=ff00 bmask=ff amask=0
0.0,0.0 1024.0x768.0 DirectColorModel: rmask=ff0000 gmask=ff00 bmask=ff amask=0
0.0,0.0 1024.0x768.0 DirectColorModel: rmask=ff0000 gmask=ff00 bmask=ff amask=0
0.0,0.0 1024.0x768.0 DirectColorModel: rmask=ff0000 gmask=ff00 bmask=ff amask=0
0.0,0.0 1024.0x768.0 DirectColorModel: rmask=ff0000 gmask=ff00 bmask=ff amask=0
1024.0,0.0 1024.0x768.0 DirectColorModel: rmask=ff0000 gmask=ff00 bmask=ff amask=0
1024.0,0.0 1024.0x768.0 DirectColorModel: rmask=ff0000 gmask=ff00 bmask=ff amask=0
1024.0,0.0 1024.0x768.0 DirectColorModel: rmask=ff0000 gmask=ff00 bmask=ff amask=0
1024.0,0.0 1024.0x768.0 DirectColorModel: rmask=ff0000 gmask=ff00 bmask=ff amask=0
1024.0,0.0 1024.0x768.0 DirectColorModel: rmask=ff0000 gmask=ff00 bmask=ff amask=0
1024.0,0.0 1024.0x768.0 DirectColorModel: rmask=ff0000 gmask=ff00 bmask=ff amask=0

例如，我期望一个能够2048x768的设备，因为它们组合在一起（我点击了“扩展桌面”）。

答案 1

对于Ash的代码，一个更通用的解决方案是合并所有图形配置的边界。

Rectangle2D result = new Rectangle2D.Double();
GraphicsEnvironment localGE = GraphicsEnvironment.getLocalGraphicsEnvironment();
for (GraphicsDevice gd : localGE.getScreenDevices()) {
  for (GraphicsConfiguration graphicsConfiguration : gd.getConfigurations()) {
    result.union(result, graphicsConfiguration.getBounds(), result);
  }
}
f.setSize(result.getWidth(), result.getHeight());

这将适用于垂直对齐的监视器以及水平对齐的监视器。

答案 2

您可以尝试：

int width = 0;
int height = 0;
GraphicsEnvironment ge = GraphicsEnvironment.getLocalGraphicsEnvironment();
GraphicsDevice[] gs = ge.getScreenDevices();
for (GraphicsDevice curGs : gs)
{
  DisplayMode mode = curGs.getDisplayMode();
  width += mode.getWidth();
  height = mode.getHeight();
}

这应该计算多个屏幕的总宽度。显然，它仅支持上述形式的水平对齐屏幕 - 您必须分析图形配置的边界以处理其他显示器对齐（取决于您想要使其防弹程度）。

编辑：然后设置框架的大小：f.setSize(width, height);