录制时检测静音

2022-09-02 09:56:17

如何在Java中启动录制操作时检测静音?什么是 PCM 数据?如何在 Java 中计算 PCM 数据?

我找到了解决方案:

package bemukan.voiceRecognition.speechToText;

import javax.sound.sampled.*;
import java.io.*;

public class RecordAudio {
    private File audioFile;
    protected boolean running;
    private ByteArrayOutputStream out;
    private AudioInputStream inputStream;
    final static float MAX_8_BITS_SIGNED = Byte.MAX_VALUE;
    final static float MAX_8_BITS_UNSIGNED = 0xff;
    final static float MAX_16_BITS_SIGNED = Short.MAX_VALUE;
    final static float MAX_16_BITS_UNSIGNED = 0xffff;
    private AudioFormat format;
    private float level;
    private int frameSize;

    public RecordAudio(){
         getFormat();
    }

    private AudioFormat getFormat() {
        File file = new File("src/Facebook/1.wav");
        AudioInputStream stream;
        try {
            stream = AudioSystem.getAudioInputStream(file);
            format=stream.getFormat();
            frameSize=stream.getFormat().getFrameSize();
            return stream.getFormat();
        } catch (UnsupportedAudioFileException e) {

        } catch (IOException e) {

        }
        return null;
    }

    public void stopAudio() {

        running = false;
    }

    public void recordAudio() {

        try {
            final AudioFormat format = getFormat();
            DataLine.Info info = new DataLine.Info(
                    TargetDataLine.class, format);
            final TargetDataLine line = (TargetDataLine)
                    AudioSystem.getLine(info);
            line.open(format);
            line.start();
            Runnable runner = new Runnable() {
                int bufferSize = (int) format.getSampleRate()
                        * format.getFrameSize();
                byte buffer[] = new byte[bufferSize];

                public void run() {
                     int readPoint = 0;

                    out = new ByteArrayOutputStream();
                    running = true;
                     int sum=0;
                    while (running) {
                        int count =
                              line.read(buffer, 0, buffer.length);
                              calculateLevel(buffer,0,0);
                         System.out.println(level);

                        if (count > 0) {
                            out.write(buffer, 0, count);
                        }
                    }
                    line.stop();
                }
            };
            Thread captureThread = new Thread(runner);
            captureThread.start();
        } catch (LineUnavailableException e) {
            System.err.println("Line unavailable: " + e);
            System.exit(-2);
        }
    }

    public File getAudioFile() {
        byte[] audio = out.toByteArray();
        InputStream input = new ByteArrayInputStream(audio);
        try {

            final AudioFormat format = getFormat();
            final AudioInputStream ais =
                    new AudioInputStream(input, format,
                            audio.length / format.getFrameSize());
            AudioSystem.write(ais, AudioFileFormat.Type.WAVE, new File("temp.wav"));
            input.close();
            System.out.println("New file created!");
        } catch (IOException e) {
            System.out.println(e.getMessage());
        }
        return new File("temp.wav");
    }
    private void calculateLevel (byte[] buffer,
                                 int readPoint,
                                 int leftOver) {
        int max = 0;
        boolean use16Bit = (format.getSampleSizeInBits() == 16);
        boolean signed = (format.getEncoding() ==
                          AudioFormat.Encoding.PCM_SIGNED);
        boolean bigEndian = (format.isBigEndian());
        if (use16Bit) {
            for (int i=readPoint; i<buffer.length-leftOver; i+=2) {
                int value = 0;
                // deal with endianness
                int hiByte = (bigEndian ? buffer[i] : buffer[i+1]);
                int loByte = (bigEndian ? buffer[i+1] : buffer [i]);
                if (signed) {
                    short shortVal = (short) hiByte;
                    shortVal = (short) ((shortVal << 8) | (byte) loByte);
                    value = shortVal;
                } else {
                    value = (hiByte << 8) | loByte;
                }
                max = Math.max(max, value);
            } // for
        } else {
            // 8 bit - no endianness issues, just sign
            for (int i=readPoint; i<buffer.length-leftOver; i++) {
                int value = 0;
                if (signed) {
                    value = buffer [i];
                } else {
                    short shortVal = 0;
                    shortVal = (short) (shortVal | buffer [i]);
                    value = shortVal;
                }
                max = Math.max (max, value);
            } // for
        } // 8 bit
        // express max as float of 0.0 to 1.0 of max value
        // of 8 or 16 bits (signed or unsigned)
        if (signed) {
            if (use16Bit) { level = (float) max / MAX_16_BITS_SIGNED; }
            else { level = (float) max / MAX_8_BITS_SIGNED; }
        } else {
            if (use16Bit) { level = (float) max / MAX_16_BITS_UNSIGNED; }
            else { level = (float) max / MAX_8_BITS_UNSIGNED; }
        }
    } // calculateLevel


}

答案 1

如何在Java中启动录制操作时检测静音?

计算一组声音帧的 dBRMS 值,并确定在哪个级别上将其视为“静音”。

什么是 PCM 数据?

脉冲编码调制格式的数据。

如何在 Java 中计算 PCM 数据?

我不明白这个问题。但猜测它与标签有关,我有一些坏消息。理论上,这可以使用Java语音API来完成。但显然没有可用于API的“语音到文本”实现(只有“文本到语音”)。speech-recognition


我必须计算语音识别项目的均方根值。但是我不知道如何在Java中计算。

对于由 -1 到 1 范围内的信号大小表示的单个通道,可以使用此方法。double

/** Computes the RMS volume of a group of signal sizes ranging from -1 to 1. */
public double volumeRMS(double[] raw) {
    double sum = 0d;
    if (raw.length==0) {
        return sum;
    } else {
        for (int ii=0; ii<raw.length; ii++) {
            sum += raw[ii];
        }
    }
    double average = sum/raw.length;

    double sumMeanSquare = 0d;
    for (int ii=0; ii<raw.length; ii++) {
        sumMeanSquare += Math.pow(raw[ii]-average,2d);
    }
    double averageMeanSquare = sumMeanSquare/raw.length;
    double rootMeanSquare = Math.sqrt(averageMeanSquare);

    return rootMeanSquare;
}

有一个字节缓冲区来保存行中的输入值,我应该如何处理这个缓冲区?

如果使用该方法,请将值转换为范围从 -1 到 1 的值数组。;)volumeRMS(double[])bytedouble


答案 2

您需要捕获值,例如数字静音为零或接近

请根据您的要求调整您的代码!!!在本例中,名为 UMBRAL(西班牙语中的阈值)的变量...

假设您可以访问WAV文件,如字节字节头...

private Integer Byte2PosIntBig(byte Byte24, byte Byte16, byte Byte08, byte Byte00) {
    return new Integer (
            ((Byte24) << 24)|
            ((Byte16 & 0xFF) << 16)|
            ((Byte08 & 0xFF) << 8)|
            ((Byte00 & 0xFF) << 0));
} 

以前。。。。

    RandomAccessFile RAFSource = new RandomAccessFile("your old file wav", "r");

从这里开始...

int PSData = 44;
byte[] Bytes = new byte[4];
byte[] ByteHeader = new byte[44];
RAFSource.seek(0);
RAFSource.read(ByteHeader);

int WavSize = Byte2PosIntBig(ByteHeader[43],ByteHeader[42],ByteHeader[41],ByteHeader[40]);

int NumBits = Byte2PosIntBig(ByteHeader[35],ByteHeader[34]);
int NumByte = NumBits/8;

    for (int i = PSData;i < PSData+WavSize;i+=NumByte) {
      int WavSample = 0;
      int WavResultI =0;
      int WavResultO = 0;
      if (NumByte == 2) {

          RAFSource.seek(i);
          Bytes[0] = RAFSource.readByte();
          Bytes[1] = RAFSource.readByte();
          WavSample = (int)(((Bytes[1]) << 8)|((Bytes[0] & 0xFF) << 0));
          if (Math.abs(WavSample) < UMBRAL) {
            //SILENCE DETECTED!!!
          }

      } else {
        RAFSource.seek(i);
        WavSample = (short)(RAFSource.readByte() & 0xFF);
        short sSamT = (short)WavSample;
        sSamT += 128;
        double dSamD = (double)sSamT*Multiplier;
        if ((double)sSamT < UMBRAL) {
          //SILENCE DETECTED!!!
        }
      }

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