OkHTTPClient Proxy Authentication 如何?

2022-09-02 11:41:20

问题:如何将授权代理添加到 OkHTTP。

我知道OkHTTP的构建器确实支持代理,尽管我很难设置一个代理。

/**
 * Given a Url and a base64 encoded password return the contents of a website.
 * @param urlString
 * @param password
 * @return JSON
 */
public String getURLJson(String urlString, String password) {       
        OkHttpClient client = new OkHttpClient.Builder()
                .connectTimeout(60, TimeUnit.SECONDS)
                .writeTimeout(60, TimeUnit.SECONDS)
                .readTimeout(60, TimeUnit.SECONDS)
                .build();

        Request request = new Request.Builder()
          .url(urlString)
          .get()
          .addHeader("authorization", "Basic " + password)
          .addHeader("cache-control", "no-cache")
          .build();

        Response response = null;
        try {
            response = client.newCall(request).execute();
            String string = response.body().string();
            response.body().close();
            return string;
        } catch (IOException e) {
            System.err.println("Failed scraping");
            e.printStackTrace();
        }
        return "failed";
    }

我有IP /端口/用户名/密码。

虽然我不知道如何将它们变成代理代理,然后可以在客户端中使用。SetProxy().

这似乎过于复杂,我似乎根本无法弄清楚。任何帮助将不胜感激。


答案 1

试试这个:

int proxyPort = 8080;
String proxyHost = "proxyHost";
final String username = "username";
final String password = "password";

Authenticator proxyAuthenticator = new Authenticator() {
  @Override public Request authenticate(Route route, Response response) throws IOException {
       String credential = Credentials.basic(username, password);
       return response.request().newBuilder()
           .header("Proxy-Authorization", credential)
           .build();
  }
};

OkHttpClient client = new OkHttpClient.Builder()
    .connectTimeout(60, TimeUnit.SECONDS)
    .writeTimeout(60, TimeUnit.SECONDS)
    .readTimeout(60, TimeUnit.SECONDS)
    .proxy(new Proxy(Proxy.Type.HTTP, new InetSocketAddress(proxyHost, proxyPort)))
    .proxyAuthenticator(proxyAuthenticator)
    .build();

答案 2

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