我想用一个解决方案来增强Tagir的伟大答案，以监控源端甚至中间操作的拆分（当前流API实现施加了一些限制）：
public static <E> Stream<E> proxy(Stream<E> src) {
Class<Stream<E>> sClass=(Class)Stream.class;
Class<Spliterator<E>> spClass=(Class)Spliterator.class;
return proxy(src, sClass, spClass, StreamSupport::stream);
}
public static IntStream proxy(IntStream src) {
return proxy(src, IntStream.class, Spliterator.OfInt.class, StreamSupport::intStream);
}
public static LongStream proxy(LongStream src) {
return proxy(src, LongStream.class, Spliterator.OfLong.class, StreamSupport::longStream);
}
public static DoubleStream proxy(DoubleStream src) {
return proxy(src, DoubleStream.class, Spliterator.OfDouble.class, StreamSupport::doubleStream);
}
static final Object EMPTY=new StringBuilder("empty");
static <E,S extends BaseStream<E,S>, Sp extends Spliterator<E>> S proxy(
S src, Class<S> sc, Class<Sp> spc, BiFunction<Sp,Boolean,S> f) {
final class Node<T> implements InvocationHandler,Runnable,
Consumer<Object>, IntConsumer, LongConsumer, DoubleConsumer {
final Class<? extends Spliterator> type;
Spliterator<T> src;
Object first=EMPTY, last=EMPTY;
Node<T> left, right;
Object currConsumer;
public Node(Spliterator<T> src, Class<? extends Spliterator> type) {
this.src = src;
this.type=type;
}
private void value(Object t) {
if(first==EMPTY) first=t;
last=t;
}
public void accept(Object t) {
value(t); ((Consumer)currConsumer).accept(t);
}
public void accept(int t) {
value(t); ((IntConsumer)currConsumer).accept(t);
}
public void accept(long t) {
value(t); ((LongConsumer)currConsumer).accept(t);
}
public void accept(double t) {
value(t); ((DoubleConsumer)currConsumer).accept(t);
}
public void run() {
System.out.println();
finish().forEach(System.out::println);
}
public Object invoke(Object proxy, Method method, Object[] args) throws Throwable {
Node<T> curr=this; while(curr.right!=null) curr=curr.right;
if(method.getName().equals("tryAdvance")||method.getName().equals("forEachRemaining")) {
curr.currConsumer=args[0];
args[0]=curr;
}
if(method.getName().equals("trySplit")) {
Spliterator s=curr.src.trySplit();
if(s==null) return null;
Node<T> pfx=new Node<>(s, type);
pfx.left=curr.left; curr.left=pfx;
curr.right=new Node<>(curr.src, type);
src=null;
return pfx.create();
}
return method.invoke(curr.src, args);
}
Object create() {
return Proxy.newProxyInstance(null, new Class<?>[]{type}, this);
}
String pad(String s, int left, int len) {
if (len == s.length())
return s;
char[] result = new char[len];
Arrays.fill(result, ' ');
s.getChars(0, s.length(), result, left);
return new String(result);
}
public List<String> finish() {
String cur = toString();
if (left == null) {
return Collections.singletonList(cur);
}
List<String> l = left.finish();
List<String> r = right.finish();
int len1 = l.get(0).length();
int len2 = r.get(0).length();
int totalLen = len1 + len2 + 1;
int leftAdd = 0;
if (cur.length() < totalLen) {
cur = pad(cur, (totalLen - cur.length()) / 2, totalLen);
} else {
leftAdd = (cur.length() - totalLen) / 2;
totalLen = cur.length();
}
List<String> result = new ArrayList<>();
result.add(cur);
char[] dashes = new char[totalLen];
Arrays.fill(dashes, ' ');
Arrays.fill(dashes, len1 / 2 + leftAdd + 1, len1 + len2 / 2 + 1
+ leftAdd, '_');
int mid = totalLen / 2;
dashes[mid] = '/';
dashes[mid + 1] = '\\';
result.add(new String(dashes));
Arrays.fill(dashes, ' ');
dashes[len1 / 2 + leftAdd] = '|';
dashes[len1 + len2 / 2 + 1 + leftAdd] = '|';
result.add(new String(dashes));
int maxSize = Math.max(l.size(), r.size());
for (int i = 0; i < maxSize; i++) {
String lstr = l.size() > i ? l.get(i) : String.format("%"
+ len1 + "s", "");
String rstr = r.size() > i ? r.get(i) : String.format("%"
+ len2 + "s", "");
result.add(pad(lstr + " " + rstr, leftAdd, totalLen));
}
return result;
}
private Object first() {
if(left==null) return first;
Object o=left.first();
if(o==EMPTY) o=right.first();
return o;
}
private Object last() {
if(right==null) return last;
Object o=right.last();
if(o==EMPTY) o=left.last();
return o;
}
public String toString() {
Object o=first(), p=last();
return o==EMPTY? "(empty)": "["+o+(o!=p? ".."+p+']': "]");
}
}
Node<E> n=new Node<>(src.spliterator(), spc);
Sp sp=(Sp)Proxy.newProxyInstance(null, new Class<?>[]{n.type}, n);
return f.apply(sp, true).onClose(n);
}
它允许使用代理包装拆分器，该代理将监视拆分操作和遇到的对象。块处理的逻辑类似于Tagir的，事实上，我复制了他的结果打印例程。
您可以传入流的源或已附加相同操作的流。（在后一种情况下，您应该尽早申请流）。正如 Tagir 所解释的那样，在大多数情况下，拆分行为取决于源和配置的并行度，因此，在大多数情况下，监视中间状态可能会更改值，但不会更改已处理的块：.parallel()
try(IntStream is=proxy(IntStream.range(0, 100).parallel())) {
is.filter(i -> i/20%2==0)
.mapToObj(ix->"\""+ix+'"')
.forEach(s->{});
}
将打印
[0..99]
___________________________________/\________________________________
| |
[0..49] [50..99]
_________________/\______________ _________________/\________________
| | | |
[0..24] [25..49] [50..74] [75..99]
________/\_____ ________/\_______ ________/\_______ ________/\_______
| | | | | | | |
[0..11] [12..24] [25..36] [37..49] [50..61] [62..74] [75..86] [87..99]
___/\_ ___/\___ ___/\___ ___/\___ ___/\___ ___/\___ ___/\___ ___/\___
| | | | | | | | | | | | | | | |
[0..5] [6..11] [12..17] [18..24] [25..30] [31..36] [37..42] [43..49] [50..55] [56..61] [62..67] [68..74] [75..80] [81..86] [87..92] [93..99]
而
try(Stream<String> s=proxy(IntStream.range(0, 100).parallel().filter(i -> i/20%2==0)
.mapToObj(ix->"\""+ix+'"'))) {
s.forEach(str->{});
}
将打印
["0".."99"]
___________________________________________/\___________________________________________
| |
["0".."49"] ["50".."99"]
____________________/\______________________ ______________________/\___________________
| | | |
["0".."19"] ["40".."49"] ["50".."59"] ["80".."99"]
____________/\_________ ____________/\______ _______/\___________ ____________/\________
| | | | | | | |
["0".."11"] ["12".."19"] (empty) ["40".."49"] ["50".."59"] (empty) ["80".."86"] ["87".."99"]
_____/\___ _____/\_____ ___/\__ _____/\_____ _____/\_____ ___/\__ _____/\__ _____/\_____
| | | | | | | | | | | | | | | |
["0".."5"] ["6".."11"] ["12".."17"] ["18".."19"] (empty) (empty) ["40".."42"] ["43".."49"] ["50".."55"] ["56".."59"] (empty) (empty) ["80"] ["81".."86"] ["87".."92"] ["93".."99"]
正如我们在这里所看到的，我们正在监视结果，但块显然是由源确定的，可能会根据过滤器的条件在下游产生空块。.filter(…).mapToObj(…)
请注意，我们可以将源监控与 Tagir 的收集器监控相结合：
try(IntStream s=proxy(IntStream.range(0, 100))) {
s.parallel().filter(i -> i/20%2==0)
.boxed().collect(parallelVisualize())
.forEach(System.out::println);
}
这将打印（请注意，输出是首先打印的）：collect
[0..99]
________________________________/\_______________________________
| |
[0..49] [50..99]
________________/\______________ _______________/\_______________
| | | |
[0..19] [40..49] [50..59] [80..99]
________/\_____ ________/\______ _______/\_______ ________/\_____
| | | | | | | |
[0..11] [12..19] (empty) [40..49] [50..59] (empty) [80..86] [87..99]
___/\_ ___/\___ ___/\__ ___/\___ ___/\___ ___/\__ ___/\_ ___/\___
| | | | | | | | | | | | | | | |
[0..5] [6..11] [12..17] [18..19] (empty) (empty) [40..42] [43..49] [50..55] [56..59] (empty) (empty) [80] [81..86] [87..92] [93..99]
[0..99]
___________________________________/\________________________________
| |
[0..49] [50..99]
_________________/\______________ _________________/\________________
| | | |
[0..24] [25..49] [50..74] [75..99]
________/\_____ ________/\_______ ________/\_______ ________/\_______
| | | | | | | |
[0..11] [12..24] [25..36] [37..49] [50..61] [62..74] [75..86] [87..99]
___/\_ ___/\___ ___/\___ ___/\___ ___/\___ ___/\___ ___/\___ ___/\___
| | | | | | | | | | | | | | | |
[0..5] [6..11] [12..17] [18..24] [25..30] [31..36] [37..42] [43..49] [50..55] [56..61] [62..67] [68..74] [75..80] [81..86] [87..92] [93..99]
我们可以清楚地看到处理块是如何匹配的，但是在过滤之后，有些块的元素较少，其中一些是完全空的。
这是演示的地方，其中两种监视方法可以产生重大影响：
try(DoubleStream is=proxy(DoubleStream.iterate(0, i->i+1)).parallel().limit(100)) {
is.boxed()
.collect(parallelVisualize())
.forEach(System.out::println);
}
[0.0..99.0]
___________________________________________________/\________________________________________________
| |
[0.0..49.0] [50.0..99.0]
_________________________/\______________________ _________________________/\________________________
| | | |
[0.0..24.0] [25.0..49.0] [50.0..74.0] [75.0..99.0]
____________/\_________ ____________/\___________ ____________/\___________ ____________/\___________
| | | | | | | |
[0.0..11.0] [12.0..24.0] [25.0..36.0] [37.0..49.0] [50.0..61.0] [62.0..74.0] [75.0..86.0] [87.0..99.0]
_____/\___ _____/\_____ _____/\_____ _____/\_____ _____/\_____ _____/\_____ _____/\_____ _____/\_____
| | | | | | | | | | | | | | | |
[0.0..5.0] [6.0..11.0] [12.0..17.0] [18.0..24.0] [25.0..30.0] [31.0..36.0] [37.0..42.0] [43.0..49.0] [50.0..55.0] [56.0..61.0] [62.0..67.0] [68.0..74.0] [75.0..80.0] [81.0..86.0] [87.0..92.0] [93.0..99.0]
[0.0..10239.0]
_____________________________/\_____
| |
[0.0..1023.0] [1024.0..10239.0]
____________________/\_______
| |
[1024.0..3071.0] [3072.0..10239.0]
____________/\______
| |
[3072.0..6143.0] [6144.0..10239.0]
___/\_______
| |
[6144.0..10239.0] (empty)
这证明了Tagir已经解释过的内容，具有未知大小的流分裂得很差，甚至提供了良好估计的可能性（实际上，无限+极限在理论上是可预测的），实现也没有利用它的任何优势。limit(…)
源被拆分为多个块，利用 的批大小 ，在每次拆分后增加，创建超出 所施加范围的块。我们还可以看到每次如何拆分前缀。10241024limit
但是当我们查看终端拆分输出时，我们可以看到，在这些多余块之间，已经丢弃了第一个块的另一个拆分。由于此块由中间数组后端，该中间数组在第一次拆分时已由默认实现填充，因此我们不会在源位置注意到它，但我们可以在终端操作中看到此数组已被拆分（不出所料）平衡良好。
因此，我们需要两种监控方式来全面了解这里...
