Draft 在使用 java-websocket 库连接到 coinbase exchange websocket 流时拒绝握手

2022-09-03 16:14:15

我正在尝试使用TooTallNate的Java-Websocket库来创建一个websocket客户端,该客户端从coinbase交换websocket流接收消息。我正在将我用Python制作的程序移植到Java中,因为Python中存在并行化瓶颈,据我所知,我在Java中所做的与在Python中所做的一样。以下是我的代码,用于使用此websocket库在Python中打开连接(这按预期工作):

ws = websocket.create_connection("wss://ws-feed.exchange.coinbase.com", 20)
            ws.send(json.dumps({
            "type": "subscribe",
            "product_id": "BTC-USD"
        }))

这是我的整个Java类:

public class CoinbaseWebsocketClient extends WebSocketClient {

private final Gson gson = new Gson();

private CoinbaseWebsocketClient(URI serverURI) {
    super(serverURI, new Draft_17());
    connect();
}

private static URI uri;
private static CoinbaseWebsocketClient coinbaseWebsocketClient;

static {
    try {
        uri = new URI("wss://ws-feed.exchange.coinbase.com");
    } catch (URISyntaxException e) {
        e.printStackTrace();
    }
}

protected static CoinbaseWebsocketClient get() {
    if (coinbaseWebsocketClient == null) {
        coinbaseWebsocketClient = new CoinbaseWebsocketClient(uri);
    }
    return coinbaseWebsocketClient;
}

@Override
public void onOpen(ServerHandshake serverHandshake) {
    System.out.println("Websocket open");
    final JsonObject btcUSD_Request = new JsonObject();
    btcUSD_Request.addProperty("type", "subscribe");
    btcUSD_Request.addProperty("product_id", "BTC_USD");
    final String requestString = gson.toJson(btcUSD_Request);
    send(requestString);
}

@Override
public void onMessage(String s) {
    System.out.println("Message received: " + s);
}

@Override
public void onClose(int code, String reason, boolean remote) {
    System.out.println("Websocket closed: " + reason);
}

@Override
public void onError(Exception e) {
    System.err.println("an error occurred:" + e);
}

}

我知道我的Java代码没有一个完全根本的问题,因为当我使用 ws://echo.websocket.org 作为URI而不是 wss://ws-feed.exchange.coinbase.com 时,它会按预期工作。但是,当我尝试连接到 wss://ws-feed.exchange.coinbase.com 时,我收到此错误:

Websocket closed: draft org.java_websocket.drafts.Draft_17@7ca2fefb refuses handshake

据我所知,这种连接没有身份验证或类似的东西(我没有在我的Python程序中提供任何东西),所以我不知道这个错误的来源是什么。


答案 1

需要创建如下 sslcontext。它跳过证书。我成功地在没有证书的情况下建立了连接

SSLContext sslContext = SSLContext.getInstance("SSL");

// set up a TrustManager that trusts everything
sslContext.init(null, new TrustManager[] { new X509TrustManager() {
            public X509Certificate[] getAcceptedIssuers() {
                    System.out.println("getAcceptedIssuers =============");
                    return null;
            }

            public void checkClientTrusted(X509Certificate[] certs,
                            String authType) {
                    System.out.println("checkClientTrusted =============");
            }

            public void checkServerTrusted(X509Certificate[] certs,
                            String authType) {
                    System.out.println("checkServerTrusted =============");
            }
} }, new SecureRandom());

答案 2

在执行 之前,您需要调用 setSocket() 方法,例如:connect()

private CoinbaseWebsocketClient(URI serverURI) {
    super(serverURI, new Draft_17());
    setSocket(SSLSocketFactory.getDefault().createSocket(serverURI.getHost(), serverURI.getPort()));
    connect();
}

祝你好运!


注意:请注意,如果发生任何故障,您的单例可能不是一个好主意(如果我没记错的话,客户端类在不可恢复的错误后不可用,您必须创建一个新的客户端才能恢复)。get()


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