PBEKeySpec 使用字节数组参数而不是 ASCII

以下是我的解决方案：我把它放在谷歌上。请考虑我必须在内部复制密码和盐，因为它们来自外部时具有另一种格式，但结果是相同的。它似乎有效并解决了将密码作为byte[]而不是char[]的问题（它让我发疯），我希望它有帮助！干杯，苏斯塔

public class Pbkdf2 {

    public Pbkdf2() {
    }

    public void GenerateKey(final byte[] masterPassword, int masterPasswordLen,
                            final byte[] salt, int saltLen,
                            int iterationCount, int requestedKeyLen,
                            byte[] generatedKey) {

        byte[] masterPasswordInternal = new byte[masterPasswordLen];
        System.arraycopy(masterPassword, 0, masterPasswordInternal, 0, masterPasswordLen);
        byte[] saltInternal = new byte[saltLen];
        System.arraycopy(salt, 0, saltInternal, 0, saltLen);


        SecretKeySpec keyspec = new SecretKeySpec(masterPasswordInternal, "HmacSHA1");
        Mac prf = null;
        try {
            prf = Mac.getInstance("HmacSHA1");
            prf.init(keyspec);
        } catch (NoSuchAlgorithmException e) {
            e.printStackTrace();
        } catch (InvalidKeyException e) {
            e.printStackTrace();
        }

        int hLen = prf.getMacLength();   // 20 for SHA1
        int l = Math.max(requestedKeyLen, hLen); //  1 for 128bit (16-byte) keys
        int r = requestedKeyLen - (l - 1) * hLen;      // 16 for 128bit (16-byte) keys
        byte T[] = new byte[l * hLen];
        int ti_offset = 0;
        for (int i = 1; i <= l; i++) {
            F(T, ti_offset, prf, saltInternal, iterationCount, i);
            ti_offset += hLen;
        }

        System.arraycopy(T, 0, generatedKey, 0, requestedKeyLen);
    }

    private static void F(byte[] dest, int offset, Mac prf, byte[] S, int c, int blockIndex) {
        final int hLen = prf.getMacLength();
        byte U_r[] = new byte[hLen];
        // U0 = S || INT (i);
        byte U_i[] = new byte[S.length + 4];
        System.arraycopy(S, 0, U_i, 0, S.length);
        INT(U_i, S.length, blockIndex);
        for (int i = 0; i < c; i++) {
            U_i = prf.doFinal(U_i);
            xor(U_r, U_i);
        }

        System.arraycopy(U_r, 0, dest, offset, hLen);
    }

    private static void xor(byte[] dest, byte[] src) {
        for (int i = 0; i < dest.length; i++) {
            dest[i] ^= src[i];
        }
    }

    private static void INT(byte[] dest, int offset, int i) {
        dest[offset + 0] = (byte) (i / (256 * 256 * 256));
        dest[offset + 1] = (byte) (i / (256 * 256));
        dest[offset + 2] = (byte) (i / (256));
        dest[offset + 3] = (byte) (i);
    }
}

我必须实现一个两阶段的 pbkdf2 派生（所以第二个 pbkdf2 的字节来自第一个作为输入）。我最终使用了BouncyCastle，因为我无法让字节数组来字符数组体操。从另一个问题中感谢Pasi：用于JAVA的PBKDF2-HMAC-SHA256的可靠实现

import org.bouncycastle.crypto.generators.PKCS5S2ParametersGenerator;
import org.bouncycastle.crypto.digests.SHA256Digest;
import org.bouncycastle.crypto.digests.GeneralDigest;
import org.bouncycastle.crypto.params.KeyParameter;

GeneraDigest algorithm = new SHA256Digest();
PKCS5S2ParametersGenerator gen = new PKCS5S2ParametersGenerator(algorithm);
gen.init(passwordBytes, salt, iterations);
byte[] dk = ((KeyParameter) gen.generateDerivedParameters(256)).getKey();