处理Spring Security中基本身份验证的未经授权的错误消息

java spring-security

2022-09-04 03:05:46

我正在尝试在我的Web应用程序中使用Spring Security 3.0.5。基本上，我希望有一个Web服务，它通过以json格式返回数据。HTTP GET

我已经实现了一个RESTful服务，当请求URL时返回数据。这适用于以下 curl 命令http://localhost:8080/webapp/json

> curl http://localhost:8080/webapp/json
{"key":"values"}

使用spring安全性添加基本身份验证后，我可以使用以下命令来获取数据

> curl  http://localhost:8080/webapp/json
<html><head><title>Apache Tomcat/6.0.29 - Error report .....
> curl -u username:password http://localhost:8080/webapp/json
{"key":"values"}

前一个命令返回标准的tomcat错误页面，因为现在它需要用户名和密码。我的问题是，是否有可能以打印出我自己的错误消息的方式处理被拒绝的访问？即

> curl  http://localhost:8080/webapp/json
{"error":"401", "message":"Username and password required"}

这是我的弹簧安全配置和.如您所见，我正在尝试添加它只是通过servlet响应打印出一个字符串，但它仍然不会在命令行上打印我自己的消息。AccessDeniedHandleraccess-denied-handler

<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns="http://www.springframework.org/schema/security"
       xmlns:beans="http://www.springframework.org/schema/beans"
       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
       xmlns:context="http://www.springframework.org/schema/context"
       xmlns:p="http://www.springframework.org/schema/p"
       xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
          http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd
          http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security-3.0.xsd">
    <global-method-security secured-annotations="enabled"/>

    <beans:bean name="access-denied" class="webapp.error.JSONAccessDeniedHandler"></beans:bean>

    <http auto-config="true">
        <access-denied-handler ref="access-denied"/>
        <intercept-url pattern="/json" access="ROLE_USER,ROLE_ADMIN"  />
        <http-basic />
    </http>

    <authentication-manager>
        <authentication-provider>
            <password-encoder hash="md5"/>
            <user-service>
            ...
            </user-service>
        </authentication-provider>
    </authentication-manager>

</beans:beans>

AccessDeniedHandler.java

package webapp.error;

import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import org.springframework.security.access.AccessDeniedException;
import org.springframework.security.web.access.AccessDeniedHandler;

public class JSONAccessDeniedHandler implements AccessDeniedHandler  {

    @Override
    public void handle(HttpServletRequest request, HttpServletResponse response, AccessDeniedException accessDeniedException) throws IOException, ServletException {
        PrintWriter writer = response.getWriter();
        writer.print("{\"error\":\"401\", \"message\":\"Username and password required\"}");
    }

}

答案 1

我已经解决了我的问题，所以我认为我应该在这里分享它。此配置允许服务器根据请求软件以不同的方式发送错误消息。如果请求来自Web浏览器，它将检查标题并在必要时重定向到表单登录名。例如，如果请求来自，它将在身份验证失败时打印出纯文本错误消息。User-Agentcurl

<?xml version="1.0" encoding="UTF-8"?>
<beans
    xmlns="http://www.springframework.org/schema/beans"
    xmlns:sec="http://www.springframework.org/schema/security"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns:context="http://www.springframework.org/schema/context"
    xmlns:p="http://www.springframework.org/schema/p"
    xsi:schemaLocation="
        http://www.springframework.org/schema/beans    http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
        http://www.springframework.org/schema/context  http://www.springframework.org/schema/context/spring-context-3.0.xsd
        http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security-3.0.xsd">

    <!-- AspectJ pointcut expression that locates our "post" method and applies security that way
    <protect-pointcut expression="execution(* bigbank.*Service.post*(..))" access="ROLE_TELLER"/>-->
    <sec:global-method-security secured-annotations="enabled"/>

    <bean id="basicAuthenticationFilter"
          class="org.springframework.security.web.authentication.www.BasicAuthenticationFilter"
          p:authenticationManager-ref="authenticationManager"
          p:authenticationEntryPoint-ref="basicAuthenticationEntryPoint" />

    <bean id="basicAuthenticationEntryPoint"
          class="webapp.PlainTextBasicAuthenticationEntryPoint"
          p:realmName="myWebapp"/>

    <bean id="formAuthenticationEntryPoint"
          class="org.springframework.security.web.authentication.LoginUrlAuthenticationEntryPoint"
          p:loginFormUrl="/login.jsp"/>

    <bean id="daep" class="org.springframework.security.web.authentication.DelegatingAuthenticationEntryPoint">
        <constructor-arg>
            <map>
                <entry key="hasHeader('User-Agent','Mozilla') or hasHeader('User-Agent','Opera') or hasHeader('User-Agent','Explorer')" value-ref="formAuthenticationEntryPoint" />
            </map>
        </constructor-arg>
        <property name="defaultEntryPoint" ref="basicAuthenticationEntryPoint"/>
    </bean>

    <sec:http entry-point-ref="daep">
        <sec:intercept-url pattern="/login.jsp*" filters="none"/>
        <sec:intercept-url pattern="/json" access="ROLE_USER,ROLE_ADMIN"  />
        <sec:intercept-url pattern="/json/*" access="ROLE_USER,ROLE_ADMIN"  />
        <sec:logout
            logout-url="/logout"
            logout-success-url="/home.jsp"/>
        <sec:form-login
            login-page="/login.jsp"
            login-processing-url="/login"
            authentication-failure-url="/login.jsp?login_error=1" default-target-url="/home.jsp"/>
        <sec:custom-filter position="BASIC_AUTH_FILTER" ref="basicAuthenticationFilter" />
    </sec:http>

    <sec:authentication-manager alias="authenticationManager">
        <sec:authentication-provider>
        ...
        </sec:authentication-provider>
    </sec:authentication-manager>

</beans>

PlainTextBasicAuthenticationEntryPoint通过扩展org.springframework.security.web.authentication.www.BasicAuthenticationEntryPoint

import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import org.springframework.security.core.AuthenticationException;
import org.springframework.security.web.authentication.www.BasicAuthenticationEntryPoint;

public class PlainTextBasicAuthenticationEntryPoint extends BasicAuthenticationEntryPoint {

    @Override
    public void commence(HttpServletRequest request, HttpServletResponse response, AuthenticationException authException) throws IOException, ServletException {
        response.addHeader("WWW-Authenticate", "Basic realm=\"" + getRealmName() + "\"");
        response.setStatus(HttpServletResponse.SC_UNAUTHORIZED);
        PrintWriter writer = response.getWriter();
        writer.println("HTTP Status " + HttpServletResponse.SC_UNAUTHORIZED + " - " + authException.getMessage());
    }
}

答案 2

我想知道它是否曾经进入你的AccessDeniedHandler。错误是由于身份验证还是授权造成的？AccessDeniedHandeler 是否同时被调用？我现在正在自己解决这个问题。