无法将类型封送为 XML 元素,因为缺少@XmlRootElement批注
2022-09-04 07:47:28
我想将对象封送到 XML。
但是,它失败,但有异常:
javax.xml.bind.MarshalException
- with linked exception:
[com.sun.istack.SAXException2: unable to marshal type "FreightOfferDetail" as an element because it is missing an @XmlRootElement annotation]
at com.sun.xml.bind.v2.runtime.MarshallerImpl.write(MarshallerImpl.java:331)
at com.sun.xml.bind.v2.runtime.MarshallerImpl.marshal(MarshallerImpl.java:257)
at javax.xml.bind.helpers.AbstractMarshallerImpl.marshal(AbstractMarshallerImpl.java:96)
at com.wktransportservices.fx.test.util.jaxb.xmltransformer.ObjectTransformer.toXML(ObjectTransformer.java:27)
at com.wktransportservices.fx.test.sampler.webservice.connect.FreightOfferToConnectFreight.runTest(FreightOfferToConnectFreight.java:59)
at org.apache.jmeter.protocol.java.sampler.JavaSampler.sample(JavaSampler.java:191)
at org.apache.jmeter.threads.JMeterThread.process_sampler(JMeterThread.java:429)
at org.apache.jmeter.threads.JMeterThread.run(JMeterThread.java:257)
at java.lang.Thread.run(Thread.java:662)
Caused by: com.sun.istack.SAXException2: unable to marshal type "FreightOfferDetail" as an element because it is missing an @XmlRootElement annotation
at com.sun.xml.bind.v2.runtime.XMLSerializer.reportError(XMLSerializer.java:244)
at com.sun.xml.bind.v2.runtime.ClassBeanInfoImpl.serializeRoot(ClassBeanInfoImpl.java:303)
at com.sun.xml.bind.v2.runtime.XMLSerializer.childAsRoot(XMLSerializer.java:490)
at com.sun.xml.bind.v2.runtime.MarshallerImpl.write(MarshallerImpl.java:328)
实际上,此注释存在(对于父类和交付的类):
@XmlRootElement(name = "Freight_Offer")
@XmlAccessorType(XmlAccessType.FIELD)
@JsonIgnoreProperties(ignoreUnknown = true)
@JsonInclude(JsonInclude.Include.NON_EMPTY)
public class FreightOffer {
@JsonIgnore
@XmlTransient
private String freightId;
private String id;
private String externalSystemId;
private AddressLocation pickUp;
private AddressLocation delivery;
private FreightDescription freightDescription;
private ListContacts contacts;
private Customer customer;
private ListSla slas;
private String pushId;
private CompanyProfile company;
private Route route;
private String href;
private Lifecycle lifecycle;
private Visibility visibility;
private Boolean unfoldedVXMatching;
// getters / setters
儿童班:
@XmlAccessorType(XmlAccessType.PROPERTY)
public class FreightOfferDetail extends FreightOffer {
private List<Contact> contact;
@XmlElement(name = "contacts")
@JsonProperty("contacts")
public List<Contact> getContact() {
return contact;
}
public void setContact(List<Contact> contact) {
this.contact = contact;
}
它在此方法下完全失败:toXML()
public class ObjectTransformer<T> implements Transformer<T> {
protected final JAXBContext context;
protected final Marshaller marshaller;
protected final int okStatusCode = 200;
protected final String okSubErrorCode = "OK";
public ObjectTransformer(JAXBContext context) throws JAXBException {
this.context = context;
marshaller = context.createMarshaller();
marshaller.setProperty("jaxb.encoding", "UTF-8");
marshaller.setProperty("jaxb.formatted.output", Boolean.TRUE);
}
public String toXML(T object) throws JAXBException {
StringWriter writer = new StringWriter();
marshaller.marshal(object, writer);
String xmlOffer = writer.toString();
return xmlOffer;
}
它应该有效,但它不应该。
我在这里找不到遗漏或错误的内容。
更新:
这是来自测试的片段:
public SampleResult runTest(JavaSamplerContext context) {
AbstractSamplerResults results = new XMLSamplerResults(new SampleResult());
results.startAndPauseSampler();
if (failureCause != null) {
results.setExceptionFailure("FAILED TO INSTANTIATE connectTransformer", failureCause);
} else {
FreightOfferDTO offer = null;
FreightOffer freightOffer = null;
try {
results.resumeSampler();
RouteInfo routeDTO = SamplerUtils.getRandomRouteFromRepo(context.getIntParameter(ROUTES_TOUSE_KEY));
offer = FreightProvider.createRandomFreight(routeDTO, createUserWithLoginOnly(context));
freightOffer = connectTransformer.fromDTO(offer);
String xmlOfferString = connectTransformer.toXML(freightOffer); // <- it fails here.
我从CSV文件中获取日期并转换为DTO对象。此方法返回到我FreightOfferDetail.
下面是此方法的代码段:
public FreightOfferDetail freightFromDTO(FreightOfferDTO freightDTO, boolean fullFormat){
FreightOfferDetail freight = new FreightOfferDetail();
freight.setFreightId(freightDTO.getIds().getAtosId());
freight.setId(freightDTO.getIds().getFxId());
// ...
在这种情况下,如何将对象封送到XML文件?