在 JPA 中选择具有 1 个条件的每个用户的最近日期的行

我有这个实体，我想为每个设备列出属性消息 = 1 的最后一个事件

@Entity
@Table(name = "t_device_event")
@NamedQueries(value = { 
@NamedQuery(name = "DeviceEvent.findWithMessageActive",
            query = "from DeviceEvent as de1 where de1.message = 1 and de1.received = " 
                  + " ( select max(de2.received) from DeviceEvent de2 " 
                  + " where de2.device.id = de1.device.id )  "), )
public class DeviceEvent {
     ..
}

但是我在上一个测试中有一个断言问题，因为它被认为是最后一个事件，而不是事实。device3

assertTrue ((numDevicesWithActiveMessage+1) == deviceEventService.findWithActiveMessage().size());

DeviceEvent deviceEvent3 = newDeviceEvent();
deviceEvent3.setMessage(1);
deviceEventService.save(deviceEvent3);

DeviceEvent deviceEvent4 = newDeviceEvent();
deviceEventService.save(deviceEvent4);

assertTrue ((numDevicesWithActiveMessage+1) == deviceEventService.findWithActiveMessage().size());