如何处理多态性的反序列化？

java gson

2022-09-01 09:52:22

我有一个类，如：

public class Barn {
    String type;
    Animal animal;
}

public class Horse extends Animal {
}

public class Cow extends Animal {
}

我想序列化它们的列表：

List<Barn> barns = new ArrayList<Barn>();

Barn barn1 = new Barn();
barn1.setType("horse");
barn1.setAnimal(new Horse());
barns.add(barn1);

Barn barn2 = new Barn();
barn2.setType("cow");
barn2.setAnimal(new Cow());
barns.add(barn2);

...

Group<Barn> barns = gson.fromJson(serialized);

序列化时，Animal 属性的类型信息将丢失。有没有办法以某种方式安装解析器侦听器，以便我可以在遇到列表中的每个元素时提供正确的类来反序列化？这就是手动提供描述类类型的字符串背后的想法。

谢谢

答案 1

在Gson项目代码库中是 RuntimeTypeAdapter，据报道，它适用于多态序列化和反序列化。我不认为我还没有尝试过使用它。有关详细信息，请参阅 http://code.google.com/p/google-gson/issues/detail?id=231。请注意，它尚未包含在任何Gson版本中。

如果使用它不符合您的需求，则需要自定义反序列化处理。下面是一种这样的方法，假设您要使用演示的 JSON 结构。（如果JSON结构可能不同，我会采取一种不同的方法。

import java.lang.reflect.Type;
import java.util.HashMap;
import java.util.List;
import java.util.Map;

import com.google.gson.Gson;
import com.google.gson.GsonBuilder;
import com.google.gson.JsonDeserializationContext;
import com.google.gson.JsonDeserializer;
import com.google.gson.JsonElement;
import com.google.gson.JsonObject;
import com.google.gson.JsonParseException;
import com.google.gson.reflect.TypeToken;

public class App
{
  public static void main(String[] args)
  {
    Barn[] barns = {new Barn(), new Barn()};
    barns[0].type = "horse";
    barns[0].animal = new Horse();
    barns[1].type = "cow";
    barns[1].animal = new Cow();

    String json = new Gson().toJson(barns);
    // [{"type":"horse","animal":{}},{"type":"cow","animal":{}}]

    BarnDeserializer deserializer = new BarnDeserializer("type");
    deserializer.registerBarnType("horse", Horse.class);
    deserializer.registerBarnType("cow", Cow.class);
    Gson gson = new GsonBuilder().registerTypeAdapter(Barn.class, deserializer).create();

    List<Barn> barns2= gson.fromJson(json, new TypeToken<List<Barn>>(){}.getType());
    for (Barn barn : barns2)
    {
      System.out.println(barn.animal.getClass());
    }
  }
}

class BarnDeserializer implements JsonDeserializer<Barn>
{
  String barnTypeElementName;
  Gson gson;
  Map<String, Class<? extends Animal>> barnTypeRegistry;

  BarnDeserializer(String barnTypeElementName)
  {
    this.barnTypeElementName = barnTypeElementName;
    gson = new Gson();
    barnTypeRegistry = new HashMap<>(); // Java 7 required for this syntax.
  }

  void registerBarnType(String barnTypeName, Class<? extends Animal> animalType)
  {
    barnTypeRegistry.put(barnTypeName, animalType);
  }

  @Override
  public Barn deserialize(JsonElement json, Type typeOfT, JsonDeserializationContext context) 
      throws JsonParseException
  {
    JsonObject barnObject = json.getAsJsonObject();
    JsonElement animalTypeElement = barnObject.get(barnTypeElementName);
    Barn barn = new Barn();
    barn.type = animalTypeElement.getAsString(); 
    Class<? extends Animal> animalType = barnTypeRegistry.get(barn.type);
    barn.animal = gson.fromJson(barnObject.get("animal"), animalType);
    return barn;
  }
}

class Barn {String type; Animal animal;}
class Animal {}
class Horse extends Animal {}
class Cow extends Animal {}

答案 2

你可以使用Gson Fire来做到这一点。代码将如下所示：

GsonFireBuilder builder = new GsonFireBuilder()
    .registerTypeSelector(Barn.class, new TypeSelector<Barn>() {
        @Override
        public Class<? extends Barn> getClassForElement(JsonElement readElement) {
            String type = readElement.getAsJsonObject().get("type").getAsString();
            if(type.equals("horse")){
                return Horse.class; 
            } else if(type.equals("cow")) {
                return Cow.class;
            } else {
                return null; //returning null will trigger Gson's default behavior
            }
        }
    });
Gson gson = builder.createGson();