当使用Apache-POI库获取单元格内容时，我得到“无法从文本单元格中获取数值”和相反的情况。我该如何修复它？

java xlsx apache-poi illegalstateexception

2022-09-01 21:29:28

我意识到这个问题有点令人困惑，但我不知道如何措辞。无论如何，这是原始代码：

private void readFile(String excelFileName) throws FileNotFoundException, IOException {
    XSSFWorkbook workbook = new XSSFWorkbook(new FileInputStream(excelFileName));
    if (workbook.getNumberOfSheets() > 1){
        System.out.println("Please make sure there is only one sheet in the excel workbook.");
    }
    XSSFSheet sheet = workbook.getSheetAt(0);
    int numOfPhysRows = sheet.getPhysicalNumberOfRows();
    XSSFRow row;
    XSSFCell num;
    for(int y = 1;y < numOfPhysRows;y++){    //start at the 2nd row since 1st should be category names
        row = sheet.getRow(y);
        poNum = row.getCell(1);
        item = new Item(Integer.parseInt(poNum.getStringCellValue());
        itemList.add(item);
        y++;
    }
}

private int poiConvertFromStringtoInt(XSSFCell cell){
    int x = Integer.parseInt(Double.toString(cell.getNumericCellValue()));
    return x;
}

我收到以下错误：

Exception in thread "main" java.lang.IllegalStateException: Cannot get a numeric value from a text cell
    at org.apache.poi.xssf.usermodel.XSSFCell.typeMismatch(XSSFCell.java:781)
    at org.apache.poi.xssf.usermodel.XSSFCell.getNumericCellValue(XSSFCell.java:199)

即使我改变它以获得一个字符串使用甚至，我得到上述错误消息的相反（并且我确保最终使它成为一个int using）。XSSFCell.getStringCellValue()XFFSCell.getRichTextValueInteger.parseInt(XSSFCell.getStringCellValue()

然后，错误显示为：

Exception in thread "main" java.lang.IllegalStateException: Cannot get a text value from a numeric cell
    at org.apache.poi.xssf.usermodel.XSSFCell.typeMismatch(XSSFCell.java:781)
    at org.apache.poi.xssf.usermodel.XSSFCell.getNumericCellValue(XSSFCell.java:199)

我知道一个事实，Excel电子表格列实际上是一个字符串。我无法更改Excel工作表，因为它是上传的，否则总是使用相同的格式，并且格式化每列首先需要花费很多处理时间。

有什么建议吗？

[解决方案]以下是我从@Wivani的帮助下想出的解决方案代码：

private long poiGetCellValue(XSSFCell cell){
    long x;
    if(cell.getCellType() == 0)
        x = (long)cell.getNumericCellValue();
    else if(cell.getCellType() == 1)
        x = Long.parseLong(cell.getStringCellValue());
    else
        x = -1;
    return x;
}

答案 1

Use This as reference

switch (cell.getCellType()) {
                case Cell.CELL_TYPE_STRING:
                    System.out.println(cell.getRichStringCellValue().getString());
                    break;
                case Cell.CELL_TYPE_NUMERIC:
                    if (DateUtil.isCellDateFormatted(cell)) {
                        System.out.println(cell.getDateCellValue());
                    } else {
                        System.out.println(cell.getNumericCellValue());
                    }
                    break;
                case Cell.CELL_TYPE_BOOLEAN:
                    System.out.println(cell.getBooleanCellValue());
                    break;
                case Cell.CELL_TYPE_FORMULA:
                    System.out.println(cell.getCellFormula());
                    break;
                default:
                    System.out.println();
            }

答案 2

您可以使用为此单元格定义的格式将值作为字符串：

final DataFormatter df = new DataFormatter();
final XSSFCell cell = row.getCell(cellIndex);
String valueAsString = df.formatCellValue(cell);

感谢这个答案。