从 HttpServletRequest 获取 POST 请求正文

2022-08-31 06:41:33

我试图从HttpServletRequest对象中获取整个身体。

我遵循的代码如下所示:

if ( request.getMethod().equals("POST") )
{
    StringBuffer sb = new StringBuffer();
    BufferedReader bufferedReader = null;
    String content = "";

    try {
        //InputStream inputStream = request.getInputStream();
        //inputStream.available();
        //if (inputStream != null) {
        bufferedReader =  request.getReader() ; //new BufferedReader(new InputStreamReader(inputStream));
        char[] charBuffer = new char[128];
        int bytesRead;
        while ( (bytesRead = bufferedReader.read(charBuffer)) != -1 ) {
            sb.append(charBuffer, 0, bytesRead);
        }
        //} else {
        //        sb.append("");
        //}

    } catch (IOException ex) {
        throw ex;
    } finally {
        if (bufferedReader != null) {
            try {
                bufferedReader.close();
            } catch (IOException ex) {
                throw ex;
            }
        }
    }

    test = sb.toString();
}

我正在用curl和wget测试功能,如下所示:

curl --header "MD5: abcd" -F "fileupload=@filename.txt http://localhost:8080/abcd.html"

wget --header="MD5: abcd" --post-data='{"imei":"351553012623446","hni":"310150","wdp":false}' http://localhost:8080/abcd.html"

但是 没有返回任何内容,因此我在 StringBuffer 上没有附加任何内容。while ( (bytesRead = bufferedReader.read(charBuffer)) != -1 )


答案 1

在Java 8中,你可以用一种更简单干净的方式做到这一点:

if ("POST".equalsIgnoreCase(request.getMethod())) 
{
   test = request.getReader().lines().collect(Collectors.joining(System.lineSeparator()));
}

答案 2

与commons-io的简单方法。

IOUtils.toString(request.getReader());

https://commons.apache.org/proper/commons-io/javadocs/api-2.5/org/apache/commons/io/IOUtils.html