JOptionPane 是/否选项确认对话框问题

java swing jfilechooser

2022-08-31 13:56:15

我已经创建了一个，它只有两个按钮。JOptionPaneYES_NO_OPTION

弹出后，我想单击以继续打开，如果我单击它应该取消操作。JOptionPane.showConfirmDialogYES BUTTONJFileChooserNO BUTTON

这似乎很容易，但我不确定我的错误在哪里。

代码段：

if (textArea.getLineCount() >= 1) {  //The condition to show the dialog if there is text inside the textArea

    int dialogButton = JOptionPane.YES_NO_OPTION;
    JOptionPane.showConfirmDialog (null, "Would You Like to Save your Previous Note First?","Warning",dialogButton);

    if (dialogButton == JOptionPane.YES_OPTION) { //The ISSUE is here

    JFileChooser saveFile = new JFileChooser();
    int saveOption = saveFile.showSaveDialog(frame);
    if(saveOption == JFileChooser.APPROVE_OPTION) {

    try {
        BufferedWriter fileWriter = new BufferedWriter(new FileWriter(saveFile.getSelectedFile().getPath()));
        fileWriter.write(textArea.getText());
        fileWriter.close();
    } catch(Exception ex) {

    }
}

答案 1

您需要查看调用的返回值。即：showConfirmDialog

int dialogResult = JOptionPane.showConfirmDialog (null, "Would You Like to Save your Previous Note First?","Warning",dialogButton);
if(dialogResult == JOptionPane.YES_OPTION){
  // Saving code here
}

您正在测试，您用它来设置对话框应显示的按钮，并且此变量从未更新过 - 因此永远不会是除 .dialogButtondialogButtonJOptionPane.YES_NO_OPTION

根据 Javadoc for ：showConfirmDialog

返回：一个整数，指示用户选择的选项

答案 2

试试这个，

int dialogButton = JOptionPane.YES_NO_OPTION;
int dialogResult = JOptionPane.showConfirmDialog(this, "Your Message", "Title on Box", dialogButton);
if(dialogResult == 0) {
  System.out.println("Yes option");
} else {
  System.out.println("No Option");
}