如何使用参数化运行JUnitSPringJUnit4ClassRunner？

java junit spring spring-test

2022-08-31 14:46:33

由于重复的注释，以下代码无效：@RunWith

@RunWith(SpringJUnit4ClassRunner.class)
@RunWith(Parameterized.class)
@SpringApplicationConfiguration(classes = {ApplicationConfigTest.class})
public class ServiceTest {
}

但是，如何结合使用这两个注释呢？

答案 1

您可以使用SpringClassRule和SpringMethodRule - 与Spring一起提供

import org.junit.ClassRule;
import org.junit.Rule;
import org.junit.Test;
import org.junit.runner.RunWith;
import org.junit.runners.Parameterized;
import org.springframework.test.context.junit4.rules.SpringClassRule;
import org.springframework.test.context.junit4.rules.SpringMethodRule;

@RunWith(Parameterized.class)
@ContextConfiguration(...)
public class MyTest {

    @ClassRule
    public static final SpringClassRule SPRING_CLASS_RULE = new SpringClassRule();

    @Rule
    public final SpringMethodRule springMethodRule = new SpringMethodRule();

    ...

答案 2

至少有2个选项可以做到这一点：

后续 http://www.blog.project13.pl/index.php/coding/1077/runwith-junit4-with-both-springjunit4classrunner-and-parameterized/

您的测试需要如下所示：

 @RunWith(Parameterized.class)
 @ContextConfiguration(classes = {ApplicationConfigTest.class})
 public class ServiceTest {

     private TestContextManager testContextManager;

     @Before
     public void setUpContext() throws Exception {
         //this is where the magic happens, we actually do "by hand" what the spring runner would do for us,
        // read the JavaDoc for the class bellow to know exactly what it does, the method names are quite accurate though
       this.testContextManager = new TestContextManager(getClass());
       this.testContextManager.prepareTestInstance(this);
     }
     ...
 }

有一个github项目 https://github.com/mmichaelis/spring-aware-rule，它建立在以前的博客上，但以一种通用的方式添加了支持。

@SuppressWarnings("InstanceMethodNamingConvention")
@ContextConfiguration(classes = {ServiceTest.class})
public class SpringAwareTest {

    @ClassRule
    public static final SpringAware SPRING_AWARE = SpringAware.forClass(SpringAwareTest.class);

    @Rule
    public TestRule springAwareMethod = SPRING_AWARE.forInstance(this);

    @Rule
    public TestName testName = new TestName();

    ...
}

因此，您可以有一个实现其中一种方法的基本类，以及从中继承的所有测试。