Java 8 Lambda Stream forEach with multiple statements

lambda java java-8

2022-08-31 16:06:59

I am still in the process of learning Lambda, please excuse me If I am doing something wrong

final Long tempId = 12345L;
List<Entry> updatedEntries = new LinkedList<>();

for (Entry entry : entryList) {
    entry.setTempId(tempId);
    updatedEntries.add(entityManager.update(entry, entry.getId()));
}

//entryList.stream().forEach(entry -> entry.setTempId(tempId));

Seems like can be executed for one statement only. It doesn't return updated stream or function to process further. I might have selected wrong one altogether.forEach

Can someone guide me how to do this effectively?

One more question,

public void doSomething() throws Exception {
    for(Entry entry: entryList){
        if(entry.getA() == null){
            printA() throws Exception;
        }
        if(entry.getB() == null){
            printB() throws Exception;
        }
        if(entry.getC() == null){
            printC() throws Exception;
        }
    }
}
    //entryList.stream().filter(entry -> entry.getA() == null).forEach(entry -> printA()); something like this?

How do I convert this to Lambda expression?

答案 1

Forgot to relate to the first code snippet. I wouldn't use at all. Since you are collecting the elements of the into a , it would make more sense to end the processing with . Then you would need in order to set the ID.forEachStreamListStreamcollectpeek

List<Entry> updatedEntries = 
    entryList.stream()
             .peek(e -> e.setTempId(tempId))
             .collect (Collectors.toList());

For the second snippet, can execute multiple expressions, just like any lambda expression can :forEach

entryList.forEach(entry -> {
  if(entry.getA() == null){
    printA();
  }
  if(entry.getB() == null){
    printB();
  }
  if(entry.getC() == null){
    printC();
  }
});

However (looking at your commented attempt), you can't use filter in this scenario, since you will only process some of the entries (for example, the entries for which ) if you do.entry.getA() == null

答案 2

List<String> items = new ArrayList<>();
items.add("A");
items.add("B");
items.add("C");
items.add("D");
items.add("E");

//lambda
//Output : A,B,C,D,E
items.forEach(item->System.out.println(item));

//Output : C
items.forEach(item->{
    System.out.println(item);
    System.out.println(item.toLowerCase());
  }
});