Android HttpPost:如何获得结果

2022-08-31 20:48:47

我一直在努力发送HttpPost请求并检索响应,但即使我能够建立连接,我也没有获得如何获取由请求 - 响应返回的字符串消息

 HttpClient httpclient = new DefaultHttpClient();
 HttpPost httppost = new HttpPost("http://www.myurl.com/app/page.php");
 // Add your data   
 List < NameValuePair > nameValuePairs = new ArrayList < NameValuePair > (5);
 nameValuePairs.add(new BasicNameValuePair("type", "20"));
 nameValuePairs.add(new BasicNameValuePair("mob", "919895865899"));
 nameValuePairs.add(new BasicNameValuePair("pack", "0"));
 nameValuePairs.add(new BasicNameValuePair("exchk", "1"));

 try {
     httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
     Log.d("myapp", "works till here. 2");
     try {
         HttpResponse response = httpclient.execute(httppost);
         Log.d("myapp", "response " + response.getEntity());
     } catch (ClientProtocolException e) {
         e.printStackTrace();
     } catch (IOException e) {
         e.printStackTrace();
     }
 } catch (UnsupportedEncodingException e) {
     e.printStackTrace();
 } 

对不起,我听起来很天真,因为我是Java的新手。请帮帮我。


答案 1

尝试在响应中使用 :EntityUtil

String responseBody = EntityUtils.toString(response.getEntity());

答案 2
    URL url;
    url = new URL("http://www.url.com/app.php");
    URLConnection connection;
    connection = url.openConnection();
    HttpURLConnection httppost = (HttpURLConnection) connection;
    httppost.setDoInput(true);
    httppost.setDoOutput(true);
    httppost.setRequestMethod("POST");
    httppost.setRequestProperty("User-Agent", "Tranz-Version-t1.914");
    httppost.setRequestProperty("Accept_Language", "en-US");
    httppost.setRequestProperty("Content-Type",
            "application/x-www-form-urlencoded");
    DataOutputStream dos = new DataOutputStream(httppost.getOutputStream());
    dos.write(b); // bytes[] b of post data

    String reply;
    InputStream in = httppost.getInputStream();
    StringBuffer sb = new StringBuffer();
    try {
        int chr;
        while ((chr = in.read()) != -1) {
            sb.append((char) chr);
        }
        reply = sb.toString();
    } finally {
        in.close();
    }

此代码段有效。我在搜索后得到了它,但是来自J2ME代码。


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