分段文件上传弹簧启动
2022-09-01 05:01:47
Im 使用 Spring Boot 并希望使用控制器接收分段文件上传。发送文件时,我不断收到错误415不受支持的内容类型响应,并且从未到达控制器
There was an unexpected error (type=Unsupported Media Type, status=415).
Content type 'multipart/form-data;boundary=----WebKitFormBoundary1KvzQ1rt2V1BBbb8' not supported
Ive 尝试在 html/jsp 页面中使用 form:action 发送,并在使用 RestTemplate 的独立客户端应用程序中发送。所有尝试都给出相同的结果
multipart/form-data;boundary=XXXXX not supported.
从多部分文档中可以看出,边界参数必须添加到分段上传中,但这似乎与控制器接收不匹配"multipart/form-data"
我的控制器方法设置如下
@RequestMapping(value = "/things", method = RequestMethod.POST, consumes = "multipart/form-data" ,
produces = { "application/json", "application/xml" })
public ResponseEntity<ThingRepresentation> submitThing(HttpServletRequest request,
@PathVariable("domain") String domainParam,
@RequestParam(value = "type") String thingTypeParam,
@RequestBody MultipartFile[] submissions) throws Exception
使用豆类设置
@Bean
public MultipartConfigElement multipartConfigElement() {
return new MultipartConfigElement("");
}
@Bean
public MultipartResolver multipartResolver() {
org.springframework.web.multipart.commons.CommonsMultipartResolver multipartResolver = new org.springframework.web.multipart.commons.CommonsMultipartResolver();
multipartResolver.setMaxUploadSize(1000000);
return multipartResolver;
}
如您所见,我已将消耗类型设置为“多部分/表单数据”,但是当发送多部分时,它必须具有边界参数并放置一个随机边界字符串。
任何人都可以告诉我如何在控制器中设置内容类型以匹配或更改我的请求以匹配我的控制器设置?
我试图发送...尝试 1...
<html lang="en">
<body>
<br>
<h2>Upload New File to this Bucket</h2>
<form action="http://localhost:8280/appname/domains/abc/things?type=abcdef00-1111-4b38-8026-315b13dc8706" method="post" enctype="multipart/form-data">
<table width="60%" border="1" cellspacing="0">
<tr>
<td width="35%"><strong>File to upload</strong></td>
<td width="65%"><input type="file" name="file" /></td>
</tr>
<tr>
<td> </td>
<td><input type="submit" name="submit" value="Add" /></td>
</tr>
</table>
</form>
</body>
</html>
尝试 2....
RestTemplate template = new RestTemplate();
MultiValueMap<String, Object> parts = new LinkedMultiValueMap<String, Object>();
parts.add("file", new FileSystemResource(pathToFile));
try{
URI response = template.postForLocation(url, parts);
}catch(HttpClientErrorException e){
System.out.println(e.getResponseBodyAsString());
}
尝试 3...
FormHttpMessageConverter formHttpMessageConverter = new FormHttpMessageConverter();
formHttpMessageConverter.setCharset(Charset.forName("UTF8"));
RestTemplate restTemplate = new RestTemplate();
restTemplate.getMessageConverters().add( formHttpMessageConverter );
restTemplate.getMessageConverters().add(new MappingJackson2HttpMessageConverter());
restTemplate.setRequestFactory(new HttpComponentsClientHttpRequestFactory());
MultiValueMap<String, Object> map = new LinkedMultiValueMap<String, Object>();
map.add("file", new FileSystemResource(path));
HttpHeaders imageHeaders = new HttpHeaders();
imageHeaders.setContentType(MediaType.MULTIPART_FORM_DATA);
HttpEntity<MultiValueMap<String, Object>> imageEntity = new HttpEntity<MultiValueMap<String, Object>>(map, imageHeaders);
ResponseEntity e= restTemplate.exchange(uri, HttpMethod.POST, imageEntity, Boolean.class);
System.out.println(e.toString());