在java中受密码保护的zip文件

java zip

2022-09-01 06:35:30

我使用java创建了zip文件，如下代码片段所示

import java.io.*;
import java.util.zip.*;

public class ZipCreateExample {
  public static void main(String[] args) throws IOException {
    System.out.print("Please enter file name to zip : ");
    BufferedReader input = new BufferedReader
        (new InputStreamReader(System.in));
    String filesToZip = input.readLine();
    File f = new File(filesToZip);
    if(!f.exists()) {
      System.out.println("File not found.");
      System.exit(0);
    }
    System.out.print("Please enter zip file name : ");
    String zipFileName = input.readLine();
    if (!zipFileName.endsWith(".zip"))
      zipFileName = zipFileName + ".zip";
    byte[] buffer = new byte[18024];
    try {
      ZipOutputStream out = new ZipOutputStream
          (new FileOutputStream(zipFileName));
      out.setLevel(Deflater.DEFAULT_COMPRESSION);
      FileInputStream in = new FileInputStream(filesToZip);
      out.putNextEntry(new ZipEntry(filesToZip));
      int len;
      while ((len = in.read(buffer)) > 0) {
        out.write(buffer, 0, len);
      }
      out.closeEntry();
      in.close();
      out.close();
    } catch (IllegalArgumentException iae) {
      iae.printStackTrace();
      System.exit(0);
    } catch (FileNotFoundException fnfe) {
      fnfe.printStackTrace();
      System.exit(0);
    } catch (IOException ioe) {
      ioe.printStackTrace();
      System.exit(0);
    }
  }
}

现在我希望当我单击zip文件时，它应该提示我键入密码，然后解压缩zip文件。请任何帮助，我应该如何走得更远？

答案 1

请尝试以下基于 Zip4j 的代码：

import net.lingala.zip4j.core.ZipFile;
import net.lingala.zip4j.exception.ZipException;
import net.lingala.zip4j.model.ZipParameters;
import net.lingala.zip4j.util.Zip4jConstants;
import org.apache.commons.io.FilenameUtils;

import java.io.File;

public class Zipper
{
    private String password;
    private static final String EXTENSION = "zip";

    public Zipper(String password)
    {
        this.password = password;
    }

    public void pack(String filePath) throws ZipException
    {
        ZipParameters zipParameters = new ZipParameters();
        zipParameters.setCompressionMethod(Zip4jConstants.COMP_DEFLATE);
        zipParameters.setCompressionLevel(Zip4jConstants.DEFLATE_LEVEL_ULTRA);
        zipParameters.setEncryptFiles(true);
        zipParameters.setEncryptionMethod(Zip4jConstants.ENC_METHOD_AES);
        zipParameters.setAesKeyStrength(Zip4jConstants.AES_STRENGTH_256);
        zipParameters.setPassword(password);
        String baseFileName = FilenameUtils.getBaseName(filePath);
        String destinationZipFilePath = baseFileName + "." + EXTENSION;
        ZipFile zipFile = new ZipFile(destinationZipFilePath);
        zipFile.addFile(new File(filePath), zipParameters);
    }

    public void unpack(String sourceZipFilePath, String extractedZipFilePath) throws ZipException
    {
        ZipFile zipFile = new ZipFile(sourceZipFilePath + "." + EXTENSION);

        if (zipFile.isEncrypted())
        {
            zipFile.setPassword(password);
        }

        zipFile.extractAll(extractedZipFilePath);
    }
}

FilenameUtils来自Apache Commons IO。

用法示例：

public static void main(String[] arguments) throws ZipException
{
    Zipper zipper = new Zipper("password");
    zipper.pack("encrypt-me.txt");
    zipper.unpack("encrypt-me", "D:\\");
}

答案 2

标准 Java API 不支持受密码保护的 zip 文件。幸运的是，好人已经为我们实现了这种能力。请看一下这篇文章，其中解释了如何创建受密码保护的zip。
（链接已失效，最新存档版本：https://web.archive.org/web/20161029174700/http://java.sys-con.com/node/1258827)