py4J最简单的例子最终更新和解决方案:
我在Python的虚拟环境中使用pip进行了安装。我写了一个超级简单的例子来测试,但它无法编译,即py4J
conda
AdditionApplication.java
py4J
javac AdditionApplication.java
未定义的投诉失败。GatewayServer
我对Python很了解,但不幸的是,我不擅长Java。我还需要提供什么?
public class AdditionApplication {
public int addition(int first, int second) {
return first + second;
}
public static void main(String[] args) {
AdditionApplication app = new AdditionApplication();
// app is now the gateway.entry_point
GatewayServer server = new GatewayServer(app);
server.start();
}
}
如果这很重要,我安装了以下版本的Java:
java -version
java version "1.7.0_51"
Java(TM) SE Runtime Environment (build 1.7.0_51-b13)
Java HotSpot(TM) 64-Bit Server VM (build 24.51-b03, mixed mode)
更新 1
在我添加:到文件顶部后,我得到了一个不同的错误:import py4j.GatewayServer;
package py4j does not exist
更新 2
pip install py4j
在 下留下了一个文件。我已将其添加到我的类路径中:jar
<PATH_TO_CONDA_ENVIRONMENT>/share/py4j/py4j0.8.1.jar
javac -cp <PATH_TO_CONDA_ENVIRONMENT>/share/py4j/py4j0.8.1.jar AdditionApplication.java
并输出
AdditionApplication.class
如何运行它?
最终更新和解决方案:
应用前面的修复程序后,我最终使用以下命令运行代码:
java -cp <PATH_TO_CONDA_ENVIRONMENT>/share/py4j/py4j0.8.1.jar AdditionApplication
代码在后台运行。要测试它:
>>> from py4j.java_gateway import JavaGateway
>>> gateway = JavaGateway() # connect to the JVM
>>> random = gateway.jvm.java.util.Random() # create a java.util.Random instance
>>> number1 = random.nextInt(10) # call the Random.nextInt method
>>> number2 = random.nextInt(10)
>>> print(number1,number2)
(2, 7)
>>> addition_app = gateway.entry_point # get the AdditionApplication instance
>>> addition_app.addition(number1,number2) # call the addition method